(x^2)-26x+88=0

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Solution for (x^2)-26x+88=0 equation:



(x^2)-26x+88=0
a = 1; b = -26; c = +88;
Δ = b2-4ac
Δ = -262-4·1·88
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-18}{2*1}=\frac{8}{2} =4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+18}{2*1}=\frac{44}{2} =22 $

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